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To print an unsigned byte you need to use %hhu. If you pass an unsigned byte then you technically have undefined behavior. Ask question asked 13 years, 3 months ago modified 13 years, 3 months ago Where the author expects it to print f0 despite the implementation having a plain char type that's signed (in which case, printf (%x, c).

Why is scanf (%hhu, char*) overwriting other variables when they are local? If you pass an unsigned byte then you technically have undefined behavior. The format %hhd is for a signed byte. Ask question asked 13 years, 3 months ago modified 13 years, 3 months ago However, in some compilers i test it in, it seems to have the range.

The format %hhd is for a signed byte. If you pass an unsigned byte then you technically have undefined behavior. Where the author expects it to print f0 despite the implementation having a plain char type that's signed (in which case, printf (%x, c) would print fffffff0 or similar). But is this expectation warranted? To print an unsigned byte you.

If you pass an unsigned byte then you technically have undefined behavior. But is this expectation warranted? Why is scanf (%hhu, char*) overwriting other variables when they are local? Where the author expects it to print f0 despite the implementation having a plain char type that's signed (in which case, printf (%x, c) would print fffffff0 or similar). As far.

To print an unsigned byte you need to use %hhu. Where the author expects it to print f0 despite the implementation having a plain char type that's signed (in which case, printf (%x, c) would print fffffff0 or similar). As far as i had understood it, the %hhu format specifier should have the range of an unsigned char. But is.